Spoiler alert! if you don’t want all of the hints to all of the puzzles revealed at this time, please go to the individual puzzle pages instead.
C(U)SI: Cold Case File
For a hint that reveals the puzzle’s theme, click here
Square 33 is filled by the word PUMPKIN
Logic Puzzles
The Student Meet Up
For a class year and building, click here
For a class year, building and restaurant, click here
Freshman, Ives, Souvlaki House
A Cornellian Quartet
For a first and last name, click here
For a first name, last name and class year, click here
For a first name, last name, class year and major, click here
Jennie Stimson ’51, mechanical engineering
For a first name, last name, class year, major and sport, click here
Jennie Stimson ’51, mechanical engineering, basketball
For a step-by-step explanation of how to eliminate possibilities and arrive at the answers to A Cornellian Quartet, click here.
Rebuses
For an explanation of how the five rebus answers are formed, click here
1) Tag + gown + knock + vowels = Taughannock Falls
2) Sh + owl + cup + F + yield = Schoellkopf Field
3) Ant + root + deck + sun + weight = Andrew Dickson White
4) Oil + in + L + eye + prayer + E = Olin Library
5) Spear + eat + off + sinks = Spirit of Zinck’s
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Cryptic Crossword
For tips on how to solve a cryptic, see this article from The Telegraph or this one from The Guardian. Fred Piscop ’70 has also published a Cryptic primer (right).
Founders Maze
To see the maze minus a section that is not needed to derive the solution, click here
Word Scramble
For the solution to the longest word (#6), click here
Symbolic Math
Solve for Nye
For a way to derive the answer, click here
From first equation:
A + A + B = 8
Subtracting 2A from both sides —> B = 8 – 2A
From second equation:
C – B = 5
adding B to both sides —> C = 5 + B
Combining these two solutions:
—> C = 5 + (8 – 2A)
—> C = 13 – 2A
From third equation:
A + 2(C) = 11
substituting our solution for C in terms of A
—> A + 2(13 – 2A) = 11
—> A + 26 – 4A = 11
subtracting 26 from both sides and collecting the A terms
—> -3A = -15
dividing both sides by -3
—> A = 5
B = 8 – 2A
substituting A = 5
—> B = 8 – 2(5)
—> B = 8 – 10
—> B = -2
C = 13 – 2A
substituting A = 5
—> C = 13 – 2(5)
—> C = 13 – 10
—> C = 3
Therefore, final equation is:
A – B – 2(C) = ?
5 – (-2) – 2(3) = ?
5 + 2 – 6 = 1
Solve for Sagan
For a way to derive the answer, click here
From third equation:
A = B + 2
Substituting into second equation:
(B+2) + B – C = -7
adding 7 to both sides —> B + 2 + B – C + 7 = 0
adding C to both sides —> B + 2 + B + 7 = C
collecting terms —> C = 2B + 9
Now we can put A and C into the first equation:
(B+2) + (B x (2B+9)) = -10
multiplying the second term —> (B+2) + (2B^2 +9B) = -10
collecting terms —> 2B^2 + 10B + 2 = -10
adding 10 to both sides —> 2B^2 + 10B + 12 = 0
dividing all terms by 2 —> B^2 + 5B + 6 = 0
Using the quadratic equation where the solution to any equation ax^2 + bx + c = 0 is:
x = [-b +/- sqrt(b^2 – 4ac)] / 2a
In our equation —> a = 1, b = 5, c = 6
Therefore:
B = [-5 +/- sqrt(5×5 – 4×6)] / 2
—> B = [-5 +/- sqrt(25 – 24)] / 2
—> B = [-5 +/- sqrt(1)] / 2
—> B = [-5 +/- 1] / 2
—> B = (-3, -2) two answers
With this answer for B, we go back to A = B + 2 —> A = (-1, 0)
C = 2B + 9 —> C = (3, 5)
Our final equation then has the following two answers:
(A x B) + (2 x C) = ?
When A = -1, B = -3, C = 3, then the answer is —> (-1 x -3) + (2 x 3) = 9
When A = 0, B = -2, C = 5, then the answer is —> (0 x -2) + (2 x 5) = 10
Cornellian ´Crostic
For the author and title of the book from which the quote is taken [filling in 23 squares of the grid] click here
Bishop, A History of Cornell
Word Search
For the six ‘bonus’ words, click here
Carl Sagan
Chapter House
Dragon Day
Give My Regards to Davy
Sage Chapel
Suspension Bridge
Cryptoquotes
#1: Reveal one letter or reveal the first two words.
#2: Reveal one letter or reveal the first two words.
#3: Reveal one letter or reveal the first two words.
#4: Reveal one letter or reveal the first two words.
#5: Reveal one letter or reveal the first two words.